ATP Challenger Tour · Round of 16 · Qingdao
Final score
Playing styles and historical archetype record
Otte
🤖 Servebot
Minaur
🎯 Baseliner
Matchup analysis
🤖 Servebot vs 🎯 Baseliner is historically tight (51% vs 49%, 4,120 matches). Neither style has a clear edge, so form, surface, and H2H matter most when Oscar Otte plays Alex de Minaur.
Hypothetical if you put 1u on each player to win every one of their matches · Last 90 days
| Metric | Otte | Minaur |
|---|---|---|
| W-L | - | 12–8 |
| Avg odds | - | 1.45 |
| ROI % | - | -12.4% |
| Units P/L | - | -2.48u |
Prior meetings and scores · 1 career meeting
1
Otte
0
Minaur
Serve and return comparison · Last 90 days
| Stat | Otte | Minaur |
|---|---|---|
| Serve | ||
| 1st Serve In % | 0% | 62.5% |
| 1st Serve Pts Won % | 0% | 64.9% |
| 2nd Serve Pts Won % | 0% | 51.8% |
| Aces / Match | 0 | 2.5 |
| Double Faults / Match | 0 | 2.3 |
| Break Points Saved % | 0% | 57.9% |
| Return | ||
| 1st Return Pts Won % | 0% | 30% |
| 2nd Return Pts Won % | 0% | 50% |
| BP Converted % | 0% | 44.7% |
| Rally | ||
| Winners / Match | 0 | 19.3 |
| Unforced Errors / Match | 0 | 32.4 |
| Net Pts Won % | 0% | 76.9% |
| Total Pts Won % | 0% | 49.3% |
| Surface (Clay) | ||
| Clay Win % | 0% | 54% |
Last five matches per player
Matchup overview
Oscar Otte and Alex de Minaur face off in the Round of 16 at Qingdao on Clay.
Oscar Otte leads 1-0 over 1 previous meeting.
Oscar Otte is 4-1 over the last 5 matches. Latest result: L vs Tom Gentzsch (Aug 18).
Alex de Minaur is 3-2 over the last 5 matches. Latest result: W vs Denis Shapovalov (Jun 17).
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