ATP Challenger Tour · Round of 16 · St. Brieuc
Final score
Prior meetings and scores · 1 career meeting
1
Stakhovsky
0
Reuter
Serve and return comparison · Last 90 days
| Stat | Stakhovsky | Reuter |
|---|---|---|
| Serve | ||
| 1st Serve In % | 0% | 0% |
| 1st Serve Pts Won % | 0% | 0% |
| 2nd Serve Pts Won % | 0% | 0% |
| Aces / Match | 0 | 0 |
| Double Faults / Match | 0 | 0 |
| Break Points Saved % | 0% | 0% |
| Return | ||
| 1st Return Pts Won % | 0% | 0% |
| 2nd Return Pts Won % | 0% | 0% |
| BP Converted % | 0% | 0% |
| Rally | ||
| Winners / Match | 0 | 0 |
| Unforced Errors / Match | 0 | 0 |
| Net Pts Won % | 0% | 0% |
| Total Pts Won % | 0% | 0% |
| Surface (Hard) | ||
| Hard Win % | 0% | 0% |
Last five matches per player
Matchup overview
Sergiy Stakhovsky and Yannik Reuter face off in the Round of 16 at St. Brieuc on Hard.
Sergiy Stakhovsky leads 1-0 over 1 previous meeting.
Sergiy Stakhovsky is 3-2 over the last 5 matches. Latest result: L vs J.J. Wolf (Jan 1).
Yannik Reuter is 2-3 over the last 5 matches. Latest result: L vs Mikael Ymer (Jan 2).
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