ATP Challenger Tour · Round of 16 · Kenitra
Final score
Prior meetings and scores · 1 career meeting
1
Arguello
0
Reuter
Serve and return comparison · Last 90 days
| Stat | Arguello | Reuter |
|---|---|---|
| Serve | ||
| 1st Serve In % | 0% | 0% |
| 1st Serve Pts Won % | 0% | 0% |
| 2nd Serve Pts Won % | 0% | 0% |
| Aces / Match | 0 | 0 |
| Double Faults / Match | 0 | 0 |
| Break Points Saved % | 0% | 0% |
| Return | ||
| 1st Return Pts Won % | 0% | 0% |
| 2nd Return Pts Won % | 0% | 0% |
| BP Converted % | 0% | 0% |
| Rally | ||
| Winners / Match | 0 | 0 |
| Unforced Errors / Match | 0 | 0 |
| Net Pts Won % | 0% | 0% |
| Total Pts Won % | 0% | 0% |
| Surface (Clay) | ||
| Clay Win % | 0% | 0% |
Last five matches per player
Matchup overview
Facundo Arguello and Yannik Reuter face off in the Round of 16 at Kenitra on Clay.
Facundo Arguello leads 1-0 over 1 previous meeting.
Facundo Arguello is 1-4 over the last 5 matches. Latest result: L vs Camilo Ugo Carabelli (Nov 30).
Yannik Reuter is 2-3 over the last 5 matches. Latest result: L vs Mikael Ymer (Jan 2).
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